Rule: Overload added beside an initializer_list overload¶
Canonical rule slug: overload-added-beside-initializer-list. ← back to all rules
A new scalar overload joins a set that already has a std::initializer_list overload, which keeps winning braced calls, so no call becomes ambiguous.
Canonical demonstration¶
- case216_overload_added_beside_initializer_list — Overload Added Beside an
initializer_listOverload (🟢 COMPATIBLE)